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Alternating Current (AC) is the standard power supply in households and industry. The calculations consider not only voltage and current but also the power factor (cos φ) and phase shift – essential for precise results.
Calculate apparent power in AC systems
Effective power considering the power factor
Calculate non-usable reactive power
Ratio of active to apparent power
Ratio of reactive to apparent power
In alternating current, the current direction changes periodically, typically at 50 Hz in Europe. A distinction is made between apparent power (S), active power (P), and reactive power (Q). The power factor cos φ describes the ratio between active and apparent power and is crucial for the efficiency of electrical systems.
Calculate the apparent power, voltage or current.
S = U × I
💡 Enter the known values – leave the field you want to calculate empty.
Example Calculation:
A 230 Volt single-phase AC motor has a rated current of 30 Ampere. What apparent power results from these values?
S = U × I
S = 230 V × 30 A
S = 6.9 kVA
Units of Measurement:
Apparent Power S = Kilovolt-Ampere [kVA]
Voltage U = Volt [V]
Current I = Ampere [A]
Calculate the active power, voltage, current or power factor.
P = U × I × cos φ
💡 Enter the known values – leave the field you want to calculate empty.
Example Calculation:
A single-phase 230 V AC motor has a rated current of 3.506 Ampere and a cos φ of 0.93. What electrical power results from these values?
P = U × I × cos φ
P = 230 V × 3.506 A × 0.93
P = 0.75 kW
Units of Measurement:
Active Power P = Kilowatt [kW]
Voltage U = Volt [V]
Current I = Ampere [A]
cos φ = unitless
Calculate the reactive power, voltage, current or sin φ.
Q = U × I × sin φ
💡 Enter the known values – leave the field you want to calculate empty.
Example Calculation:
A 230 Volt single-phase AC motor has a rated current of 8.56 Ampere and a sin φ of 0.92. What reactive power results from these values?
Q = U × I × sin φ
Q = 230 V × 8.56 A × 0.92
Q = 1.811 kVAr
Units of Measurement:
Reactive Power Q = Kilovolt-Ampere Reactive [kVAr]
Voltage U = Volt [V]
Current I = Ampere [A]
sin φ = unitless
Calculate cos φ, active power or apparent power.
cos φ = P / S
💡 Enter the known values – leave the field you want to calculate empty.
Example Calculation:
A 4.0 kW three-phase motor (or 400V electric motor) has a cos phi of 0.85. What apparent power results from these values?
cos φ = P / S
S = P / cos φ
S = 4.0 kW / 0.85
S = 4.706 kVA
Units of Measurement:
Active Power P = Kilowatt [kW]
Apparent Power S = Kilovolt-Ampere [kVA]
cos φ = unitless
Calculate sin φ, reactive power or apparent power.
sin φ = Q / S
💡 Enter the known values – leave the field you want to calculate empty.
Example Calculation:
An AC motor with apparent power of 3.2 kVA has a sin phi of 0.234. What reactive power results from these values?
sin φ = Q / S
Q = S × sin φ
Q = 3.2 kVA × 0.234
Q = 0.749 kVAr
Units of Measurement:
Reactive Power Q = Kilovolt-Ampere Reactive [kVAr]
Apparent Power S = Kilovolt-Ampere [kVA]
sin φ = unitless
Bei Wechselstrom wechselt die Stromrichtung periodisch, in Europa typischerweise mit 50 Hz. Man unterscheidet Scheinleistung (S), Wirkleistung (P) und Blindleistung (Q). Der Leistungsfaktor cos φ beschreibt das Verhältnis von Wirk- zu Scheinleistung; er steht auf dem Typenschild des Motors.
Ein 230-V-Einphasen-Wechselstrommotor hat einen Nennstrom von 30 A.
S = U × I
S = 230 V × 30 A
S = 6,9 kVA
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